Base | Representation |
---|---|
bin | 1111010100111111… |
… | …0000111000101101 |
3 | 101121202020210221111 |
4 | 3311033300320231 |
5 | 31411311102232 |
6 | 1520141032021 |
7 | 203651046343 |
oct | 36517607055 |
9 | 11552223844 |
10 | 4114550317 |
11 | 1821613609 |
12 | 969b55611 |
13 | 50758ac77 |
14 | 2b0651993 |
15 | 191351047 |
hex | f53f0e2d |
4114550317 has 2 divisors, whose sum is σ = 4114550318. Its totient is φ = 4114550316.
The previous prime is 4114550309. The next prime is 4114550351. The reversal of 4114550317 is 7130554114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4005117796 + 109432521 = 63286^2 + 10461^2 .
It is a cyclic number.
It is not a de Polignac number, because 4114550317 - 23 = 4114550309 is a prime.
It is a super-2 number, since 2×41145503172 = 33859048622249600978, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4114500317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057275158 + 2057275159.
It is an arithmetic number, because the mean of its divisors is an integer number (2057275159).
Almost surely, 24114550317 is an apocalyptic number.
It is an amenable number.
4114550317 is a deficient number, since it is larger than the sum of its proper divisors (1).
4114550317 is an equidigital number, since it uses as much as digits as its factorization.
4114550317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8400, while the sum is 31.
The square root of 4114550317 is about 64144.7606356123. The cubic root of 4114550317 is about 1602.4117686403.
The spelling of 4114550317 in words is "four billion, one hundred fourteen million, five hundred fifty thousand, three hundred seventeen".
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