Base | Representation |
---|---|
bin | 10010101101100000111101… |
… | …11010010101101000010111 |
3 | 12101200112210202121000002122 |
4 | 21112300132322111220113 |
5 | 20343120113124230421 |
6 | 223302203545130155 |
7 | 11444502542263556 |
oct | 1126603672255027 |
9 | 171615722530078 |
10 | 41146305305111 |
11 | 12124060732166 |
12 | 474651a48995b |
13 | 19c6106828756 |
14 | a236c5713d9d |
15 | 4b549a9e82ab |
hex | 256c1ee95a17 |
41146305305111 has 2 divisors, whose sum is σ = 41146305305112. Its totient is φ = 41146305305110.
The previous prime is 41146305305081. The next prime is 41146305305179. The reversal of 41146305305111 is 11150350364114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41146305305111 - 214 = 41146305288727 is a prime.
It is a super-2 number, since 2×411463053051112 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41146305305411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20573152652555 + 20573152652556.
It is an arithmetic number, because the mean of its divisors is an integer number (20573152652556).
Almost surely, 241146305305111 is an apocalyptic number.
41146305305111 is a deficient number, since it is larger than the sum of its proper divisors (1).
41146305305111 is an equidigital number, since it uses as much as digits as its factorization.
41146305305111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 35.
Adding to 41146305305111 its reverse (11150350364114), we get a palindrome (52296655669225).
The spelling of 41146305305111 in words is "forty-one trillion, one hundred forty-six billion, three hundred five million, three hundred five thousand, one hundred eleven".
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