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41148185593 is a prime number
BaseRepresentation
bin100110010100100111…
…110111101111111001
310221012200120102000211
4212110213313233321
51133232413414333
630523032231121
72654455543444
oct462447675771
9127180512024
1041148185593
11164a6094959
127b8453b4a1
133b59c04818
141dc4c9065b
15110c6d9ecd
hex9949f7bf9

41148185593 has 2 divisors, whose sum is σ = 41148185594. Its totient is φ = 41148185592.

The previous prime is 41148185591. The next prime is 41148185623. The reversal of 41148185593 is 39558184114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 35241801984 + 5906383609 = 187728^2 + 76853^2 .

It is a cyclic number.

It is not a de Polignac number, because 41148185593 - 21 = 41148185591 is a prime.

Together with 41148185591, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (41148185591) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20574092796 + 20574092797.

It is an arithmetic number, because the mean of its divisors is an integer number (20574092797).

Almost surely, 241148185593 is an apocalyptic number.

It is an amenable number.

41148185593 is a deficient number, since it is larger than the sum of its proper divisors (1).

41148185593 is an equidigital number, since it uses as much as digits as its factorization.

41148185593 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 691200, while the sum is 49.

The spelling of 41148185593 in words is "forty-one billion, one hundred forty-eight million, one hundred eighty-five thousand, five hundred ninety-three".