Base | Representation |
---|---|
bin | 100110010100100111… |
… | …110111101111111001 |
3 | 10221012200120102000211 |
4 | 212110213313233321 |
5 | 1133232413414333 |
6 | 30523032231121 |
7 | 2654455543444 |
oct | 462447675771 |
9 | 127180512024 |
10 | 41148185593 |
11 | 164a6094959 |
12 | 7b8453b4a1 |
13 | 3b59c04818 |
14 | 1dc4c9065b |
15 | 110c6d9ecd |
hex | 9949f7bf9 |
41148185593 has 2 divisors, whose sum is σ = 41148185594. Its totient is φ = 41148185592.
The previous prime is 41148185591. The next prime is 41148185623. The reversal of 41148185593 is 39558184114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 35241801984 + 5906383609 = 187728^2 + 76853^2 .
It is a cyclic number.
It is not a de Polignac number, because 41148185593 - 21 = 41148185591 is a prime.
Together with 41148185591, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (41148185591) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20574092796 + 20574092797.
It is an arithmetic number, because the mean of its divisors is an integer number (20574092797).
Almost surely, 241148185593 is an apocalyptic number.
It is an amenable number.
41148185593 is a deficient number, since it is larger than the sum of its proper divisors (1).
41148185593 is an equidigital number, since it uses as much as digits as its factorization.
41148185593 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 691200, while the sum is 49.
The spelling of 41148185593 in words is "forty-one billion, one hundred forty-eight million, one hundred eighty-five thousand, five hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •