Base | Representation |
---|---|
bin | 1111010101000111… |
… | …1000000110011001 |
3 | 101121210021221122221 |
4 | 3311101320012121 |
5 | 31411431313103 |
6 | 1520200544041 |
7 | 203655544126 |
oct | 36521700631 |
9 | 11553257587 |
10 | 4115104153 |
11 | 1821961726 |
12 | 96a182021 |
13 | 507723094 |
14 | 2b075774d |
15 | 1914101bd |
hex | f5478199 |
4115104153 has 2 divisors, whose sum is σ = 4115104154. Its totient is φ = 4115104152.
The previous prime is 4115104139. The next prime is 4115104157. The reversal of 4115104153 is 3514015114.
4115104153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2986950409 + 1128153744 = 54653^2 + 33588^2 .
It is a cyclic number.
It is not a de Polignac number, because 4115104153 - 25 = 4115104121 is a prime.
It is not a weakly prime, because it can be changed into another prime (4115104157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057552076 + 2057552077.
It is an arithmetic number, because the mean of its divisors is an integer number (2057552077).
Almost surely, 24115104153 is an apocalyptic number.
It is an amenable number.
4115104153 is a deficient number, since it is larger than the sum of its proper divisors (1).
4115104153 is an equidigital number, since it uses as much as digits as its factorization.
4115104153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 25.
The square root of 4115104153 is about 64149.0775693618. The cubic root of 4115104153 is about 1602.4836625647.
Adding to 4115104153 its reverse (3514015114), we get a palindrome (7629119267).
The spelling of 4115104153 in words is "four billion, one hundred fifteen million, one hundred four thousand, one hundred fifty-three".
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