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41151422051 is a prime number
BaseRepresentation
bin100110010100110100…
…001101111001100011
310221012220122211121122
4212110310031321203
51133234231001201
630523225442455
72654525213255
oct462464157143
9127186584548
1041151422051
11164a79a5513
127b8564042b
133b5a79899c
141dc5493cd5
15110cb28e1b
hex994d0de63

41151422051 has 2 divisors, whose sum is σ = 41151422052. Its totient is φ = 41151422050.

The previous prime is 41151422041. The next prime is 41151422071. The reversal of 41151422051 is 15022415114.

It is a happy number.

41151422051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 41151422051 - 214 = 41151405667 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 41151422051.

It is not a weakly prime, because it can be changed into another prime (41151422041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20575711025 + 20575711026.

It is an arithmetic number, because the mean of its divisors is an integer number (20575711026).

Almost surely, 241151422051 is an apocalyptic number.

41151422051 is a deficient number, since it is larger than the sum of its proper divisors (1).

41151422051 is an equidigital number, since it uses as much as digits as its factorization.

41151422051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1600, while the sum is 26.

Adding to 41151422051 its reverse (15022415114), we get a palindrome (56173837165).

The spelling of 41151422051 in words is "forty-one billion, one hundred fifty-one million, four hundred twenty-two thousand, fifty-one".