Base | Representation |
---|---|
bin | 10010101101101010101010… |
… | …11100100011011010001000 |
3 | 12101201001020211221122221211 |
4 | 21112311111130203122020 |
5 | 20343211300343231100 |
6 | 223304424535342504 |
7 | 11445045623614666 |
oct | 1126652534433210 |
9 | 171631224848854 |
10 | 41151515211400 |
11 | 12126294578940 |
12 | 4747533221a34 |
13 | 19c6756ccc639 |
14 | a23a5b615c36 |
15 | 4b56a30b41ba |
hex | 256d55723688 |
41151515211400 has 48 divisors (see below), whose sum is σ = 104375206769040. Its totient is φ = 14964187348800.
The previous prime is 41151515211271. The next prime is 41151515211491. The reversal of 41151515211400 is 411251515114.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9352614894 + ... + 9352619293.
It is an arithmetic number, because the mean of its divisors is an integer number (2174483474355).
Almost surely, 241151515211400 is an apocalyptic number.
41151515211400 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
41151515211400 is an abundant number, since it is smaller than the sum of its proper divisors (63223691557640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41151515211400 is a wasteful number, since it uses less digits than its factorization.
41151515211400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18705234214 (or 18705234205 counting only the distinct ones).
The product of its (nonzero) digits is 4000, while the sum is 31.
Adding to 41151515211400 its reverse (411251515114), we get a palindrome (41562766726514).
The spelling of 41151515211400 in words is "forty-one trillion, one hundred fifty-one billion, five hundred fifteen million, two hundred eleven thousand, four hundred".
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