Base | Representation |
---|---|
bin | 10010101101101110000101… |
… | …11000110101010011000111 |
3 | 12101201012222210221201121021 |
4 | 21112313002320311103013 |
5 | 20343224030420410010 |
6 | 223305331050132011 |
7 | 11445142260511156 |
oct | 1126670270652307 |
9 | 171635883851537 |
10 | 41153351341255 |
11 | 12127046a6a42a |
12 | 4747966121007 |
13 | 19c698a52c7ca |
14 | a23b9341559d |
15 | 4b575e3a78da |
hex | 256dc2e354c7 |
41153351341255 has 32 divisors (see below), whose sum is σ = 53177016863808. Its totient is φ = 30460389120000.
The previous prime is 41153351341231. The next prime is 41153351341301. The reversal of 41153351341255 is 55214315335114.
It is a happy number.
It is a de Polignac number, because none of the positive numbers 2k-41153351341255 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6630505 + ... + 11237005.
It is an arithmetic number, because the mean of its divisors is an integer number (1661781776994).
Almost surely, 241153351341255 is an apocalyptic number.
41153351341255 is a deficient number, since it is larger than the sum of its proper divisors (12023665522553).
41153351341255 is a wasteful number, since it uses less digits than its factorization.
41153351341255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4608307.
The product of its digits is 540000, while the sum is 43.
Adding to 41153351341255 its reverse (55214315335114), we get a palindrome (96367666676369).
The spelling of 41153351341255 in words is "forty-one trillion, one hundred fifty-three billion, three hundred fifty-one million, three hundred forty-one thousand, two hundred fifty-five".
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