Base | Representation |
---|---|
bin | 10010101101110010111111… |
… | …00110001001010111011111 |
3 | 12101201110210001010002020011 |
4 | 21112321133212021113133 |
5 | 20343244421444400011 |
6 | 223310444005304051 |
7 | 11445264363632623 |
oct | 1126713746112737 |
9 | 171643701102204 |
10 | 41155980465631 |
11 | 12128176047499 |
12 | 474837a705027 |
13 | 19c6cb912bcc5 |
14 | a23d62679183 |
15 | 4b58650dc621 |
hex | 256e5f9895df |
41155980465631 has 2 divisors, whose sum is σ = 41155980465632. Its totient is φ = 41155980465630.
The previous prime is 41155980465571. The next prime is 41155980465671. The reversal of 41155980465631 is 13656408955114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41155980465631 - 211 = 41155980463583 is a prime.
It is a super-2 number, since 2×411559804656312 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41155980465671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20577990232815 + 20577990232816.
It is an arithmetic number, because the mean of its divisors is an integer number (20577990232816).
Almost surely, 241155980465631 is an apocalyptic number.
41155980465631 is a deficient number, since it is larger than the sum of its proper divisors (1).
41155980465631 is an equidigital number, since it uses as much as digits as its factorization.
41155980465631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552000, while the sum is 58.
The spelling of 41155980465631 in words is "forty-one trillion, one hundred fifty-five billion, nine hundred eighty million, four hundred sixty-five thousand, six hundred thirty-one".
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