Base | Representation |
---|---|
bin | 111011111010001010111… |
… | …110110011010000010011 |
3 | 112120120110120012202212112 |
4 | 323322022332303100103 |
5 | 1014422413024410433 |
6 | 12431141005215535 |
7 | 603302606625062 |
oct | 73721276632023 |
9 | 15516416182775 |
10 | 4116910388243 |
11 | 1347a7664a744 |
12 | 565a74b615ab |
13 | 23b2b8b84263 |
14 | 10338c1d41d9 |
15 | 72154aba348 |
hex | 3be8afb3413 |
4116910388243 has 2 divisors, whose sum is σ = 4116910388244. Its totient is φ = 4116910388242.
The previous prime is 4116910388237. The next prime is 4116910388309. The reversal of 4116910388243 is 3428830196114.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4116910388243 - 224 = 4116893611027 is a prime.
It is a super-2 number, since 2×41169103882432 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4116910388191 and 4116910388200.
It is not a weakly prime, because it can be changed into another prime (4116910385243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2058455194121 + 2058455194122.
It is an arithmetic number, because the mean of its divisors is an integer number (2058455194122).
Almost surely, 24116910388243 is an apocalyptic number.
4116910388243 is a deficient number, since it is larger than the sum of its proper divisors (1).
4116910388243 is an equidigital number, since it uses as much as digits as its factorization.
4116910388243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 995328, while the sum is 50.
The spelling of 4116910388243 in words is "four trillion, one hundred sixteen billion, nine hundred ten million, three hundred eighty-eight thousand, two hundred forty-three".
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