Base | Representation |
---|---|
bin | 111011111010011111001… |
… | …100000011000000111111 |
3 | 112120121100012010121102101 |
4 | 323322133030003000333 |
5 | 1014424111321424431 |
6 | 12431234355405531 |
7 | 603314164336102 |
oct | 73723714030077 |
9 | 15517305117371 |
10 | 4117249404991 |
11 | 134812aa52a78 |
12 | 565b4a5b38a7 |
13 | 23b341193198 |
14 | 1033c1242739 |
15 | 72174734961 |
hex | 3be9f30303f |
4117249404991 has 2 divisors, whose sum is σ = 4117249404992. Its totient is φ = 4117249404990.
The previous prime is 4117249404929. The next prime is 4117249405079. The reversal of 4117249404991 is 1994049427114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4117249404991 - 221 = 4117247307839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4117249404901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2058624702495 + 2058624702496.
It is an arithmetic number, because the mean of its divisors is an integer number (2058624702496).
Almost surely, 24117249404991 is an apocalyptic number.
4117249404991 is a deficient number, since it is larger than the sum of its proper divisors (1).
4117249404991 is an equidigital number, since it uses as much as digits as its factorization.
4117249404991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2612736, while the sum is 55.
The spelling of 4117249404991 in words is "four trillion, one hundred seventeen billion, two hundred forty-nine million, four hundred four thousand, nine hundred ninety-one".
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