Base | Representation |
---|---|
bin | 11000100010111… |
… | …100010011111111 |
3 | 1001200220021101202 |
4 | 120202330103333 |
5 | 1320411004434 |
6 | 104510330115 |
7 | 13130232224 |
oct | 3042742377 |
9 | 1050807352 |
10 | 411813119 |
11 | 1a1504323 |
12 | b5ab993b |
13 | 67419503 |
14 | 3c99b94b |
15 | 26248a7e |
hex | 188bc4ff |
411813119 has 2 divisors, whose sum is σ = 411813120. Its totient is φ = 411813118.
The previous prime is 411813113. The next prime is 411813133. The reversal of 411813119 is 911318114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 411813119 - 212 = 411809023 is a prime.
It is a super-2 number, since 2×4118131192 = 339180089961016322, which contains 22 as substring.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 411813091 and 411813100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (411813113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205906559 + 205906560.
It is an arithmetic number, because the mean of its divisors is an integer number (205906560).
Almost surely, 2411813119 is an apocalyptic number.
411813119 is a deficient number, since it is larger than the sum of its proper divisors (1).
411813119 is an equidigital number, since it uses as much as digits as its factorization.
411813119 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 864, while the sum is 29.
The square root of 411813119 is about 20293.1791250164. The cubic root of 411813119 is about 743.9893621778.
The spelling of 411813119 in words is "four hundred eleven million, eight hundred thirteen thousand, one hundred nineteen".
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