Base | Representation |
---|---|
bin | 111011111101000100011… |
… | …001111111100010101111 |
3 | 112120212111100221112111012 |
4 | 323331010121333202233 |
5 | 1020000300423121143 |
6 | 12432413415015435 |
7 | 603442653144566 |
oct | 73750431774257 |
9 | 15525440845435 |
10 | 4120021301423 |
11 | 1349322685875 |
12 | 5665a296a57b |
13 | 23b6935306a1 |
14 | 1035a542cbdd |
15 | 72287c6c418 |
hex | 3bf4467f8af |
4120021301423 has 2 divisors, whose sum is σ = 4120021301424. Its totient is φ = 4120021301422.
The previous prime is 4120021301411. The next prime is 4120021301437. The reversal of 4120021301423 is 3241031200214.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4120021301423 - 210 = 4120021300399 is a prime.
It is a super-3 number, since 3×41200213014233 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4120021301443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2060010650711 + 2060010650712.
It is an arithmetic number, because the mean of its divisors is an integer number (2060010650712).
Almost surely, 24120021301423 is an apocalyptic number.
4120021301423 is a deficient number, since it is larger than the sum of its proper divisors (1).
4120021301423 is an equidigital number, since it uses as much as digits as its factorization.
4120021301423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 4120021301423 its reverse (3241031200214), we get a palindrome (7361052501637).
The spelling of 4120021301423 in words is "four trillion, one hundred twenty billion, twenty-one million, three hundred one thousand, four hundred twenty-three".
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