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412003203431 is a prime number
BaseRepresentation
bin1011111111011010100…
…11011111100101100111
31110101110012201021121212
411333231103133211213
523222240310002211
6513134402302035
741523552306131
oct5775523374547
91411405637555
10412003203431
11149803081836
1267a2305791b
132cb0c354c91
1415d263b6051
15aab559d38b
hex5fed4df967

412003203431 has 2 divisors, whose sum is σ = 412003203432. Its totient is φ = 412003203430.

The previous prime is 412003203419. The next prime is 412003203467. The reversal of 412003203431 is 134302300214.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-412003203431 is a prime.

It is a super-2 number, since 2×4120032034312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 412003203397 and 412003203406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (412003203481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206001601715 + 206001601716.

It is an arithmetic number, because the mean of its divisors is an integer number (206001601716).

Almost surely, 2412003203431 is an apocalyptic number.

412003203431 is a deficient number, since it is larger than the sum of its proper divisors (1).

412003203431 is an equidigital number, since it uses as much as digits as its factorization.

412003203431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 412003203431 its reverse (134302300214), we get a palindrome (546305503645).

The spelling of 412003203431 in words is "four hundred twelve billion, three million, two hundred three thousand, four hundred thirty-one".