Base | Representation |
---|---|
bin | 1011111111011011101… |
… | …10010100001000001110 |
3 | 1110101110211220001000202 |
4 | 11333231312110020032 |
5 | 23222300124102114 |
6 | 513135330053502 |
7 | 41524023014516 |
oct | 5775566241016 |
9 | 1411424801022 |
10 | 412012331534 |
11 | 149808246921 |
12 | 67a2611a292 |
13 | 2cb111cca1b |
14 | 15d276b0846 |
15 | aab62a2cde |
hex | 5fedd9420e |
412012331534 has 12 divisors (see below), whose sum is σ = 656510999784. Its totient is φ = 193888155744.
The previous prime is 412012331531. The next prime is 412012331543. The reversal of 412012331534 is 435133210214.
It is a super-2 number, since 2×4120123315342 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 412012331497 and 412012331506.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (412012331531) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 356411474 + ... + 356412629.
It is an arithmetic number, because the mean of its divisors is an integer number (54709249982).
Almost surely, 2412012331534 is an apocalyptic number.
412012331534 is a deficient number, since it is larger than the sum of its proper divisors (244498668250).
412012331534 is a wasteful number, since it uses less digits than its factorization.
412012331534 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 712824139 (or 712824122 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 412012331534 its reverse (435133210214), we get a palindrome (847145541748).
The spelling of 412012331534 in words is "four hundred twelve billion, twelve million, three hundred thirty-one thousand, five hundred thirty-four".
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