412014401 has 2 divisors, whose sum is σ = 412014402. Its totient is φ = 412014400.

The previous prime is 412014391. The next prime is 412014403. The reversal of 412014401 is 104410214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 250114225 + 161900176 = 15815^2 + 12724^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-412014401 is a prime.

Together with 412014403, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 412014401.

It is not a weakly prime, because it can be changed into another prime (412014403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206007200 + 206007201.

It is an arithmetic number, because the mean of its divisors is an integer number (206007201).

Almost surely, 2^412014401 is an apocalyptic number.

It is an amenable number.

412014401 is a deficient number, since it is larger than the sum of its proper divisors (1).

412014401 is an equidigital number, since it uses as much as digits as its factorization.

412014401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 17.

The square root of 412014401 is about 20298.1378702580. The cubic root of 412014401 is about 744.1105557229.

Adding to 412014401 its reverse (104410214), we get a palindrome (516424615).

The spelling of 412014401 in words is "four hundred twelve million, fourteen thousand, four hundred one".