412017131 has 2 divisors, whose sum is σ = 412017132. Its totient is φ = 412017130.

The previous prime is 412017121. The next prime is 412017143. The reversal of 412017131 is 131710214.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-412017131 is a prime.

It is a super-2 number, since 2×412017131² = 339516232474942322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (412017121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206008565 + 206008566.

It is an arithmetic number, because the mean of its divisors is an integer number (206008566).

Almost surely, 2^412017131 is an apocalyptic number.

412017131 is a deficient number, since it is larger than the sum of its proper divisors (1).

412017131 is an equidigital number, since it uses as much as digits as its factorization.

412017131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 20.

The square root of 412017131 is about 20298.2051176945. The cubic root of 412017131 is about 744.1121992070.

Adding to 412017131 its reverse (131710214), we get a palindrome (543727345).

The spelling of 412017131 in words is "four hundred twelve million, seventeen thousand, one hundred thirty-one".