Base | Representation |
---|---|
bin | 100110010111110101… |
… | …001111011101100001 |
3 | 10221100102212121000202 |
4 | 212113311033131201 |
5 | 1133340204202431 |
6 | 30532234154545 |
7 | 2656011260552 |
oct | 462765173541 |
9 | 127312777022 |
10 | 41202022241 |
11 | 16523516156 |
12 | 7b9a582a55 |
13 | 3b68104323 |
14 | 1dcc0a6329 |
15 | 11122c18cb |
hex | 997d4f761 |
41202022241 has 2 divisors, whose sum is σ = 41202022242. Its totient is φ = 41202022240.
The previous prime is 41202022217. The next prime is 41202022243. The reversal of 41202022241 is 14222020214.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28358560000 + 12843462241 = 168400^2 + 113329^2 .
It is a cyclic number.
It is not a de Polignac number, because 41202022241 - 230 = 40128280417 is a prime.
Together with 41202022243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (41202022243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20601011120 + 20601011121.
It is an arithmetic number, because the mean of its divisors is an integer number (20601011121).
Almost surely, 241202022241 is an apocalyptic number.
It is an amenable number.
41202022241 is a deficient number, since it is larger than the sum of its proper divisors (1).
41202022241 is an equidigital number, since it uses as much as digits as its factorization.
41202022241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 512, while the sum is 20.
Adding to 41202022241 its reverse (14222020214), we get a palindrome (55424042455).
The spelling of 41202022241 in words is "forty-one billion, two hundred two million, twenty-two thousand, two hundred forty-one".
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