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412022002442431 is a prime number
BaseRepresentation
bin101110110101110110101100…
…1000110000110000010111111
32000000211220210202211002210111
41131223231121012012002333
5413001032030111124211
64020144143405450451
7152533415213425333
oct13553553106060277
92000756722732714
10412022002442431
1110a312605a95117
123a26475ab70a27
13148b967b436234
1473a5d854417c3
1532979879b1421
hex176bb591860bf

412022002442431 has 2 divisors, whose sum is σ = 412022002442432. Its totient is φ = 412022002442430.

The previous prime is 412022002442389. The next prime is 412022002442441. The reversal of 412022002442431 is 134244200220214.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 412022002442431 - 241 = 409822979186879 is a prime.

It is a super-2 number, since 2×4120220024424312 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 412022002442393 and 412022002442402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (412022002442441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206011001221215 + 206011001221216.

It is an arithmetic number, because the mean of its divisors is an integer number (206011001221216).

Almost surely, 2412022002442431 is an apocalyptic number.

412022002442431 is a deficient number, since it is larger than the sum of its proper divisors (1).

412022002442431 is an equidigital number, since it uses as much as digits as its factorization.

412022002442431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24576, while the sum is 31.

Adding to 412022002442431 its reverse (134244200220214), we get a palindrome (546266202662645).

The spelling of 412022002442431 in words is "four hundred twelve trillion, twenty-two billion, two million, four hundred forty-two thousand, four hundred thirty-one".