Base | Representation |
---|---|
bin | 10010101111001001011000… |
… | …10010110100010110000111 |
3 | 12101212220111121200010202111 |
4 | 21113210230102310112013 |
5 | 20400024420241313111 |
6 | 223344034354121451 |
7 | 11451525666605161 |
oct | 1127445422642607 |
9 | 171786447603674 |
10 | 41202364401031 |
11 | 121459086196a9 |
12 | 4755364580287 |
13 | 19cb49b985822 |
14 | a262c2a37931 |
15 | 4b6b7c29aa21 |
hex | 25792c4b4587 |
41202364401031 has 2 divisors, whose sum is σ = 41202364401032. Its totient is φ = 41202364401030.
The previous prime is 41202364401019. The next prime is 41202364401049. The reversal of 41202364401031 is 13010446320214.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41202364401031 - 231 = 41200216917383 is a prime.
It is a super-3 number, since 3×412023644010313 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 41202364400984 and 41202364401002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41202364401131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20601182200515 + 20601182200516.
It is an arithmetic number, because the mean of its divisors is an integer number (20601182200516).
Almost surely, 241202364401031 is an apocalyptic number.
41202364401031 is a deficient number, since it is larger than the sum of its proper divisors (1).
41202364401031 is an equidigital number, since it uses as much as digits as its factorization.
41202364401031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
The spelling of 41202364401031 in words is "forty-one trillion, two hundred two billion, three hundred sixty-four million, four hundred one thousand, thirty-one".
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