Base | Representation |
---|---|
bin | 1011111111011110000… |
… | …10111101100100100111 |
3 | 1110101112020200212000201 |
4 | 11333233002331210213 |
5 | 23222320300033411 |
6 | 513141324451331 |
7 | 41524355551021 |
oct | 5775702754447 |
9 | 1411466625021 |
10 | 412032424231 |
11 | 14981861a85a |
12 | 67a309a9b47 |
13 | 2cb154163ac |
14 | 15d2a221011 |
15 | aab7e213c1 |
hex | 5fef0bd927 |
412032424231 has 2 divisors, whose sum is σ = 412032424232. Its totient is φ = 412032424230.
The previous prime is 412032424217. The next prime is 412032424261. The reversal of 412032424231 is 132424230214.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 412032424231 - 217 = 412032293159 is a prime.
It is a super-2 number, since 2×4120324242312 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 412032424231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (412032424261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206016212115 + 206016212116.
It is an arithmetic number, because the mean of its divisors is an integer number (206016212116).
Almost surely, 2412032424231 is an apocalyptic number.
412032424231 is a deficient number, since it is larger than the sum of its proper divisors (1).
412032424231 is an equidigital number, since it uses as much as digits as its factorization.
412032424231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 412032424231 its reverse (132424230214), we get a palindrome (544456654445).
The spelling of 412032424231 in words is "four hundred twelve billion, thirty-two million, four hundred twenty-four thousand, two hundred thirty-one".
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