Base | Representation |
---|---|
bin | 101110110110000011011101… |
… | …1101011001000111001001111 |
3 | 2000000221112120222022111012001 |
4 | 1131230012323223020321033 |
5 | 413002004211041434432 |
6 | 4020204520530253131 |
7 | 152535405621035653 |
oct | 13554067353107117 |
9 | 2000845528274161 |
10 | 412049426124367 |
11 | 10a3231a8a39269 |
12 | 3a269b331271a7 |
13 | 148bc12bb2a675 |
14 | 73a7427650a63 |
15 | 32985403369e7 |
hex | 176c1bbac8e4f |
412049426124367 has 2 divisors, whose sum is σ = 412049426124368. Its totient is φ = 412049426124366.
The previous prime is 412049426124313. The next prime is 412049426124407. The reversal of 412049426124367 is 763421624940214.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 412049426124367 - 27 = 412049426124239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (412049426124667) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206024713062183 + 206024713062184.
It is an arithmetic number, because the mean of its divisors is an integer number (206024713062184).
Almost surely, 2412049426124367 is an apocalyptic number.
412049426124367 is a deficient number, since it is larger than the sum of its proper divisors (1).
412049426124367 is an equidigital number, since it uses as much as digits as its factorization.
412049426124367 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13934592, while the sum is 55.
The spelling of 412049426124367 in words is "four hundred twelve trillion, forty-nine billion, four hundred twenty-six million, one hundred twenty-four thousand, three hundred sixty-seven".
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