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41210020424533 is a prime number
BaseRepresentation
bin10010101111010111101001…
…01000001110101101010101
312101220122021011211102121111
421113223310220032231111
520400141110212041113
6223351342205215021
711452216502666332
oct1127536450165525
9171818234742544
1041210020424533
1112149087206454
124756940561471
1319cc11bb7134c
14a2680b761989
154b6e7949c13d
hex257af4a0eb55

41210020424533 has 2 divisors, whose sum is σ = 41210020424534. Its totient is φ = 41210020424532.

The previous prime is 41210020424437. The next prime is 41210020424567. The reversal of 41210020424533 is 33542402001214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33111254960644 + 8098765463889 = 5754238^2 + 2845833^2 .

It is a cyclic number.

It is not a de Polignac number, because 41210020424533 - 221 = 41210018327381 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41210020424495 and 41210020424504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41210020424233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20605010212266 + 20605010212267.

It is an arithmetic number, because the mean of its divisors is an integer number (20605010212267).

Almost surely, 241210020424533 is an apocalyptic number.

It is an amenable number.

41210020424533 is a deficient number, since it is larger than the sum of its proper divisors (1).

41210020424533 is an equidigital number, since it uses as much as digits as its factorization.

41210020424533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 41210020424533 its reverse (33542402001214), we get a palindrome (74752422425747).

The spelling of 41210020424533 in words is "forty-one trillion, two hundred ten billion, twenty million, four hundred twenty-four thousand, five hundred thirty-three".