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412100243351197 is a prime number
BaseRepresentation
bin101110110110011011001000…
…0100111011110011010011101
32000001010101202111220002021021
41131230312100213132122131
5413003322244244214242
64020244123244004141
7152542155125244142
oct13554662047363235
92001111674802237
10412100243351197
1110a342805a38995
123a277955830651
13148c3b69ca235b
1473a9a887123c9
153299a16807b67
hex176cd909de69d

412100243351197 has 2 divisors, whose sum is σ = 412100243351198. Its totient is φ = 412100243351196.

The previous prime is 412100243351077. The next prime is 412100243351299. The reversal of 412100243351197 is 791153342001214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 215508829887961 + 196591413463236 = 14680219^2 + 14021106^2 .

It is a cyclic number.

It is not a de Polignac number, because 412100243351197 - 227 = 412100109133469 is a prime.

It is a super-5 number, since 5×4121002433511975 (a number of 74 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (412100243351597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206050121675598 + 206050121675599.

It is an arithmetic number, because the mean of its divisors is an integer number (206050121675599).

Almost surely, 2412100243351197 is an apocalyptic number.

It is an amenable number.

412100243351197 is a deficient number, since it is larger than the sum of its proper divisors (1).

412100243351197 is an equidigital number, since it uses as much as digits as its factorization.

412100243351197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 181440, while the sum is 43.

The spelling of 412100243351197 in words is "four hundred twelve trillion, one hundred billion, two hundred forty-three million, three hundred fifty-one thousand, one hundred ninety-seven".