Base | Representation |
---|---|
bin | 111011111110000101011… |
… | …111101101110000000011 |
3 | 112120222022110202211222101 |
4 | 323332011133231300003 |
5 | 1020010020002223301 |
6 | 12433114024451231 |
7 | 603512013150541 |
oct | 73760537556003 |
9 | 15528273684871 |
10 | 4121113320451 |
11 | 1349833039936 |
12 | 566848619b17 |
13 | 23b8088487aa |
14 | 10366a490d91 |
15 | 722eda78701 |
hex | 3bf857edc03 |
4121113320451 has 2 divisors, whose sum is σ = 4121113320452. Its totient is φ = 4121113320450.
The previous prime is 4121113320449. The next prime is 4121113320547. The reversal of 4121113320451 is 1540233111214.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4121113320451 - 21 = 4121113320449 is a prime.
It is a super-2 number, since 2×41211133204512 (a number of 26 digits) contains 22 as substring.
Together with 4121113320449, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (4121113350451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2060556660225 + 2060556660226.
It is an arithmetic number, because the mean of its divisors is an integer number (2060556660226).
Almost surely, 24121113320451 is an apocalyptic number.
4121113320451 is a deficient number, since it is larger than the sum of its proper divisors (1).
4121113320451 is an equidigital number, since it uses as much as digits as its factorization.
4121113320451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 4121113320451 its reverse (1540233111214), we get a palindrome (5661346431665).
The spelling of 4121113320451 in words is "four trillion, one hundred twenty-one billion, one hundred thirteen million, three hundred twenty thousand, four hundred fifty-one".
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