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412113433243483 is a prime number
BaseRepresentation
bin101110110110100001010001…
…0110010111010111101011011
32000001011122210202000000222101
41131231002202302322331123
5413004031302402242413
64020254144141104231
7152543133025420456
oct13555024262727533
92001148722000871
10412113433243483
1110a348364322214
123a27a416b58077
13148c518c7cc74a
1473aa57a38c49d
15329a039768edd
hex176d0a2cbaf5b

412113433243483 has 2 divisors, whose sum is σ = 412113433243484. Its totient is φ = 412113433243482.

The previous prime is 412113433243411. The next prime is 412113433243529. The reversal of 412113433243483 is 384342334311214.

It is an a-pointer prime, because the next prime (412113433243529) can be obtained adding 412113433243483 to its sum of digits (46).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 412113433243483 - 213 = 412113433235291 is a prime.

It is not a weakly prime, because it can be changed into another prime (412113433243283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206056716621741 + 206056716621742.

It is an arithmetic number, because the mean of its divisors is an integer number (206056716621742).

Almost surely, 2412113433243483 is an apocalyptic number.

412113433243483 is a deficient number, since it is larger than the sum of its proper divisors (1).

412113433243483 is an equidigital number, since it uses as much as digits as its factorization.

412113433243483 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1990656, while the sum is 46.

Adding to 412113433243483 its reverse (384342334311214), we get a palindrome (796455767554697).

The spelling of 412113433243483 in words is "four hundred twelve trillion, one hundred thirteen billion, four hundred thirty-three million, two hundred forty-three thousand, four hundred eighty-three".