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4121981347717 is a prime number
BaseRepresentation
bin111011111110111001001…
…110111110011110000101
3112121001112222010012112101
4323332321032332132011
51020013304211111332
612433340113352101
7603542353233352
oct73767116763605
915531488105471
104121981347717
11134a139013642
12566a4b268631
1323b9166292ac
1410370d887629
157234ed8bae7
hex3bfb93be785

4121981347717 has 2 divisors, whose sum is σ = 4121981347718. Its totient is φ = 4121981347716.

The previous prime is 4121981347667. The next prime is 4121981347723. The reversal of 4121981347717 is 7177431891214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3883682138436 + 238299209281 = 1970706^2 + 488159^2 .

It is a cyclic number.

It is not a de Polignac number, because 4121981347717 - 223 = 4121972959109 is a prime.

It is a super-2 number, since 2×41219813477172 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4121981347747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2060990673858 + 2060990673859.

It is an arithmetic number, because the mean of its divisors is an integer number (2060990673859).

Almost surely, 24121981347717 is an apocalyptic number.

It is an amenable number.

4121981347717 is a deficient number, since it is larger than the sum of its proper divisors (1).

4121981347717 is an equidigital number, since it uses as much as digits as its factorization.

4121981347717 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2370816, while the sum is 55.

The spelling of 4121981347717 in words is "four trillion, one hundred twenty-one billion, nine hundred eighty-one million, three hundred forty-seven thousand, seven hundred seventeen".