Base | Representation |
---|---|
bin | 1011111111111110011… |
… | …00010100000110100111 |
3 | 1110102020010102100012001 |
4 | 11333333030110012213 |
5 | 23223344121430041 |
6 | 513224242510131 |
7 | 41534155215115 |
oct | 5777714240647 |
9 | 1412203370161 |
10 | 412303311271 |
11 | 14994751a245 |
12 | 67aa7665347 |
13 | 2cb5958cb97 |
14 | 15d541b6ab5 |
15 | aad1ace131 |
hex | 5fff3141a7 |
412303311271 has 2 divisors, whose sum is σ = 412303311272. Its totient is φ = 412303311270.
The previous prime is 412303311181. The next prime is 412303311281. The reversal of 412303311271 is 172113303214.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 412303311271 - 215 = 412303278503 is a prime.
It is a super-2 number, since 2×4123033112712 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (412303311281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206151655635 + 206151655636.
It is an arithmetic number, because the mean of its divisors is an integer number (206151655636).
Almost surely, 2412303311271 is an apocalyptic number.
412303311271 is a deficient number, since it is larger than the sum of its proper divisors (1).
412303311271 is an equidigital number, since it uses as much as digits as its factorization.
412303311271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 412303311271 its reverse (172113303214), we get a palindrome (584416614485).
The spelling of 412303311271 in words is "four hundred twelve billion, three hundred three million, three hundred eleven thousand, two hundred seventy-one".
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