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412341104011141 is a prime number
BaseRepresentation
bin101110111000001011010010…
…1000001111110011110000101
32000001222102110111201100202101
41131300112211001332132011
5413021244040111324031
64020550515455512101
7152565442644131464
oct13560264501763605
92001872414640671
10412341104011141
1110a42597555a738
123a2b6575528631
13149107a3775106
1473b75b73da9db
1532a0e120be361
hex17705a507e785

412341104011141 has 2 divisors, whose sum is σ = 412341104011142. Its totient is φ = 412341104011140.

The previous prime is 412341104011069. The next prime is 412341104011229. The reversal of 412341104011141 is 141110401143214.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 394615404175041 + 17725699836100 = 19864929^2 + 4210190^2 .

It is a cyclic number.

It is not a de Polignac number, because 412341104011141 - 27 = 412341104011013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (412341104012141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206170552005570 + 206170552005571.

It is an arithmetic number, because the mean of its divisors is an integer number (206170552005571).

Almost surely, 2412341104011141 is an apocalyptic number.

It is an amenable number.

412341104011141 is a deficient number, since it is larger than the sum of its proper divisors (1).

412341104011141 is an equidigital number, since it uses as much as digits as its factorization.

412341104011141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 28.

Adding to 412341104011141 its reverse (141110401143214), we get a palindrome (553451505154355).

The spelling of 412341104011141 in words is "four hundred twelve trillion, three hundred forty-one billion, one hundred four million, eleven thousand, one hundred forty-one".