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412413001421 is a prime number
BaseRepresentation
bin1100000000001011011…
…10101111111011001101
31110102111202211011210012
412000011232233323031
523224110212021141
6513243201523005
741536656446351
oct6000556577315
91412452734705
10412413001421
111499a342a063
1267b18343465
132cb762171b5
1415d649ab461
15aadb549ceb
hex6005bafecd

412413001421 has 2 divisors, whose sum is σ = 412413001422. Its totient is φ = 412413001420.

The previous prime is 412413001411. The next prime is 412413001439. The reversal of 412413001421 is 124100314214.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 260477536900 + 151935464521 = 510370^2 + 389789^2 .

It is a cyclic number.

It is not a de Polignac number, because 412413001421 - 214 = 412412985037 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (412413001411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206206500710 + 206206500711.

It is an arithmetic number, because the mean of its divisors is an integer number (206206500711).

Almost surely, 2412413001421 is an apocalyptic number.

It is an amenable number.

412413001421 is a deficient number, since it is larger than the sum of its proper divisors (1).

412413001421 is an equidigital number, since it uses as much as digits as its factorization.

412413001421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 412413001421 its reverse (124100314214), we get a palindrome (536513315635).

The spelling of 412413001421 in words is "four hundred twelve billion, four hundred thirteen million, one thousand, four hundred twenty-one".