Base | Representation |
---|---|
bin | 101110111000111001110111… |
… | …1110101101010101001000111 |
3 | 2000002022222200102022222000112 |
4 | 1131301303233311222221013 |
5 | 413024413430142320312 |
6 | 4021104502345303235 |
7 | 152605614006221435 |
oct | 13561635765525107 |
9 | 2002288612288015 |
10 | 412441143323207 |
11 | 10a4643410a6549 |
12 | 3a311a34494b1b |
13 | 1491a05746a21b |
14 | 73bc387771d55 |
15 | 32a38199c1d22 |
hex | 1771cefd6aa47 |
412441143323207 has 2 divisors, whose sum is σ = 412441143323208. Its totient is φ = 412441143323206.
The previous prime is 412441143322987. The next prime is 412441143323263. The reversal of 412441143323207 is 702323341144214.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 412441143323207 - 214 = 412441143306823 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (412441143323267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206220571661603 + 206220571661604.
It is an arithmetic number, because the mean of its divisors is an integer number (206220571661604).
Almost surely, 2412441143323207 is an apocalyptic number.
412441143323207 is a deficient number, since it is larger than the sum of its proper divisors (1).
412441143323207 is an equidigital number, since it uses as much as digits as its factorization.
412441143323207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 387072, while the sum is 41.
The spelling of 412441143323207 in words is "four hundred twelve trillion, four hundred forty-one billion, one hundred forty-three million, three hundred twenty-three thousand, two hundred seven".
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