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412443311110111 is a prime number
BaseRepresentation
bin101110111000111010111000…
…1000011000111011111011111
32000002100012021111101221121101
41131301311301003013133133
5413024432400121010421
64021105501424413531
7152606021511134041
oct13561656103073737
92002305244357541
10412443311110111
1110a465253823976
123a31233a4772a7
131491a311600478
1473bc511625a91
1532a38e4e79191
hex1771d710c77df

412443311110111 has 2 divisors, whose sum is σ = 412443311110112. Its totient is φ = 412443311110110.

The previous prime is 412443311110081. The next prime is 412443311110121. The reversal of 412443311110111 is 111011113344214.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 412443311110111 - 27 = 412443311109983 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 412443311110111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (412443311110121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206221655555055 + 206221655555056.

It is an arithmetic number, because the mean of its divisors is an integer number (206221655555056).

Almost surely, 2412443311110111 is an apocalyptic number.

412443311110111 is a deficient number, since it is larger than the sum of its proper divisors (1).

412443311110111 is an equidigital number, since it uses as much as digits as its factorization.

412443311110111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 28.

Adding to 412443311110111 its reverse (111011113344214), we get a palindrome (523454424454325).

The spelling of 412443311110111 in words is "four hundred twelve trillion, four hundred forty-three billion, three hundred eleven million, one hundred ten thousand, one hundred eleven".