Base | Representation |
---|---|
bin | 111100000001010010010… |
… | …111010010010111010001 |
3 | 112121022012000022122011021 |
4 | 330001102113102113101 |
5 | 1020034034403043101 |
6 | 12434443050115441 |
7 | 603663130166446 |
oct | 74012227222721 |
9 | 15538160278137 |
10 | 4124550440401 |
11 | 1350237218a36 |
12 | 56744771bb81 |
13 | 23bc3596a291 |
14 | 1038b4b619cd |
15 | 724506b45a1 |
hex | 3c0525d25d1 |
4124550440401 has 2 divisors, whose sum is σ = 4124550440402. Its totient is φ = 4124550440400.
The previous prime is 4124550440371. The next prime is 4124550440447. The reversal of 4124550440401 is 1040440554214.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2512668819600 + 1611881620801 = 1585140^2 + 1269599^2 .
It is a cyclic number.
It is not a de Polignac number, because 4124550440401 - 27 = 4124550440273 is a prime.
It is not a weakly prime, because it can be changed into another prime (4124550440201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062275220200 + 2062275220201.
It is an arithmetic number, because the mean of its divisors is an integer number (2062275220201).
Almost surely, 24124550440401 is an apocalyptic number.
It is an amenable number.
4124550440401 is a deficient number, since it is larger than the sum of its proper divisors (1).
4124550440401 is an equidigital number, since it uses as much as digits as its factorization.
4124550440401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51200, while the sum is 34.
Adding to 4124550440401 its reverse (1040440554214), we get a palindrome (5164990994615).
The spelling of 4124550440401 in words is "four trillion, one hundred twenty-four billion, five hundred fifty million, four hundred forty thousand, four hundred one".
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