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412455104441 is a prime number
BaseRepresentation
bin1100000000010000011…
…11010110111110111001
31110102121201001020021022
412000020033112332321
523224202001320231
6513251304152225
741541010353602
oct6001017267671
91412551036238
10412455104441
11149a15176746
1267b2a468675
132cb81b69023
1415d6a40ada9
15aae00b4c7b
hex60083d6fb9

412455104441 has 2 divisors, whose sum is σ = 412455104442. Its totient is φ = 412455104440.

The previous prime is 412455104437. The next prime is 412455104443. The reversal of 412455104441 is 144401554214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 411419616400 + 1035488041 = 641420^2 + 32179^2 .

It is a cyclic number.

It is not a de Polignac number, because 412455104441 - 22 = 412455104437 is a prime.

Together with 412455104443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (412455104443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206227552220 + 206227552221.

It is an arithmetic number, because the mean of its divisors is an integer number (206227552221).

Almost surely, 2412455104441 is an apocalyptic number.

It is an amenable number.

412455104441 is a deficient number, since it is larger than the sum of its proper divisors (1).

412455104441 is an equidigital number, since it uses as much as digits as its factorization.

412455104441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51200, while the sum is 35.

Adding to 412455104441 its reverse (144401554214), we get a palindrome (556856658655).

The spelling of 412455104441 in words is "four hundred twelve billion, four hundred fifty-five million, one hundred four thousand, four hundred forty-one".