Base | Representation |
---|---|
bin | 1100000000010110000… |
… | …11001101001010100111 |
3 | 1110102201222202111000201 |
4 | 12000023003031022213 |
5 | 23224301034001101 |
6 | 513300110451331 |
7 | 41542122162625 |
oct | 6001303151247 |
9 | 1412658674021 |
10 | 412502250151 |
11 | 149a39847a42 |
12 | 67b42203b47 |
13 | 2cb8b8651b4 |
14 | 15d727a0515 |
15 | aae42c8e01 |
hex | 600b0cd2a7 |
412502250151 has 2 divisors, whose sum is σ = 412502250152. Its totient is φ = 412502250150.
The previous prime is 412502250103. The next prime is 412502250161. The reversal of 412502250151 is 151052205214.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 412502250151 - 213 = 412502241959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (412502250161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206251125075 + 206251125076.
It is an arithmetic number, because the mean of its divisors is an integer number (206251125076).
Almost surely, 2412502250151 is an apocalyptic number.
412502250151 is a deficient number, since it is larger than the sum of its proper divisors (1).
412502250151 is an equidigital number, since it uses as much as digits as its factorization.
412502250151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4000, while the sum is 28.
Adding to 412502250151 its reverse (151052205214), we get a palindrome (563554455365).
The spelling of 412502250151 in words is "four hundred twelve billion, five hundred two million, two hundred fifty thousand, one hundred fifty-one".
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