Base | Representation |
---|---|
bin | 111100000001110011110… |
… | …101100100000011101011 |
3 | 112121100122011001002211211 |
4 | 330001303311210003223 |
5 | 1020041212134302243 |
6 | 12435014510533551 |
7 | 604013056451332 |
oct | 74016365440353 |
9 | 15540564032754 |
10 | 4125112025323 |
11 | 13504a5219003 |
12 | 5675838072b7 |
13 | 23bcc5105853 |
14 | 103929588d19 |
15 | 72484b44d9d |
hex | 3c073d640eb |
4125112025323 has 2 divisors, whose sum is σ = 4125112025324. Its totient is φ = 4125112025322.
The previous prime is 4125112025291. The next prime is 4125112025339. The reversal of 4125112025323 is 3235202115214.
It is a happy number.
4125112025323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4125112025323 - 25 = 4125112025291 is a prime.
It is not a weakly prime, because it can be changed into another prime (4125112025393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062556012661 + 2062556012662.
It is an arithmetic number, because the mean of its divisors is an integer number (2062556012662).
Almost surely, 24125112025323 is an apocalyptic number.
4125112025323 is a deficient number, since it is larger than the sum of its proper divisors (1).
4125112025323 is an equidigital number, since it uses as much as digits as its factorization.
4125112025323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 31.
The spelling of 4125112025323 in words is "four trillion, one hundred twenty-five billion, one hundred twelve million, twenty-five thousand, three hundred twenty-three".
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