Base | Representation |
---|---|
bin | 111100000010000110111… |
… | …111001010011010110011 |
3 | 112121101110112120222222202 |
4 | 330002012333022122303 |
5 | 1020042341411340401 |
6 | 12435110425053415 |
7 | 604024040354111 |
oct | 74020677123263 |
9 | 15541415528882 |
10 | 4125433308851 |
11 | 135064a60a088 |
12 | 56765332726b |
13 | 23c04684604a |
14 | 10395a0dcab1 |
15 | 724a2e5a06b |
hex | 3c086fca6b3 |
4125433308851 has 2 divisors, whose sum is σ = 4125433308852. Its totient is φ = 4125433308850.
The previous prime is 4125433308839. The next prime is 4125433308949. The reversal of 4125433308851 is 1588033345214.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4125433308851 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4125433308796 and 4125433308805.
It is not a weakly prime, because it can be changed into another prime (4125433308251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062716654425 + 2062716654426.
It is an arithmetic number, because the mean of its divisors is an integer number (2062716654426).
Almost surely, 24125433308851 is an apocalyptic number.
4125433308851 is a deficient number, since it is larger than the sum of its proper divisors (1).
4125433308851 is an equidigital number, since it uses as much as digits as its factorization.
4125433308851 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1382400, while the sum is 47.
The spelling of 4125433308851 in words is "four trillion, one hundred twenty-five billion, four hundred thirty-three million, three hundred eight thousand, eight hundred fifty-one".
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