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41256302013541 is a prime number
BaseRepresentation
bin10010110000101101110110…
…01110011110110001100101
312102002001201121210202021201
421120112323032132301211
520401420401303413131
6223424514500242501
711455445424004606
oct1130267316366145
9172061647722251
1041256302013541
1112166776a3426a
1247638b80a0431
131a035b6442384
14a28b5c2bbdad
154b8287690761
hex2585bb39ec65

41256302013541 has 2 divisors, whose sum is σ = 41256302013542. Its totient is φ = 41256302013540.

The previous prime is 41256302013529. The next prime is 41256302013559. The reversal of 41256302013541 is 14531020365214.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23692030562916 + 17564271450625 = 4867446^2 + 4190975^2 .

It is a cyclic number.

It is not a de Polignac number, because 41256302013541 - 27 = 41256302013413 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 41256302013541.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41256302010541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20628151006770 + 20628151006771.

It is an arithmetic number, because the mean of its divisors is an integer number (20628151006771).

Almost surely, 241256302013541 is an apocalyptic number.

It is an amenable number.

41256302013541 is a deficient number, since it is larger than the sum of its proper divisors (1).

41256302013541 is an equidigital number, since it uses as much as digits as its factorization.

41256302013541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 41256302013541 its reverse (14531020365214), we get a palindrome (55787322378755).

The spelling of 41256302013541 in words is "forty-one trillion, two hundred fifty-six billion, three hundred two million, thirteen thousand, five hundred forty-one".