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41260433 is a prime number
BaseRepresentation
bin1001110101100…
…1010110010001
32212122020200012
42131121112101
541030313213
64032204305
71010464544
oct235312621
985566605
1041260433
1121321635
1211999695
138718476
1456a085b
1539504a8
hex2759591

41260433 has 2 divisors, whose sum is σ = 41260434. Its totient is φ = 41260432.

The previous prime is 41260423. The next prime is 41260441. The reversal of 41260433 is 33406214.

It is a happy number.

41260433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41113744 + 146689 = 6412^2 + 383^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41260433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41260399 and 41260408.

It is not a weakly prime, because it can be changed into another prime (41260423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20630216 + 20630217.

It is an arithmetic number, because the mean of its divisors is an integer number (20630217).

Almost surely, 241260433 is an apocalyptic number.

It is an amenable number.

41260433 is a deficient number, since it is larger than the sum of its proper divisors (1).

41260433 is an equidigital number, since it uses as much as digits as its factorization.

41260433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 41260433 is about 6423.4284459313. The cubic root of 41260433 is about 345.5502889220.

Adding to 41260433 its reverse (33406214), we get a palindrome (74666647).

The spelling of 41260433 in words is "forty-one million, two hundred sixty thousand, four hundred thirty-three".