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412623167243473 is a prime number
BaseRepresentation
bin101110111010001110101000…
…1010011110100010011010001
32000002222101111222110011221001
41131310131101103310103101
5413040404221303242343
64021324244405502001
7152625016512060634
oct13564352123642321
92002871458404831
10412623167243473
1110a5245589329aa
123a341173a11901
13149312754b2714
1473c70d4291c1b
1532a841ec1544d
hex17747514f44d1

412623167243473 has 2 divisors, whose sum is σ = 412623167243474. Its totient is φ = 412623167243472.

The previous prime is 412623167243471. The next prime is 412623167243509. The reversal of 412623167243473 is 374342761326214.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 296510732543169 + 116112434700304 = 17219487^2 + 10775548^2 .

It is a cyclic number.

It is not a de Polignac number, because 412623167243473 - 21 = 412623167243471 is a prime.

It is a super-2 number, since 2×4126231672434732 (a number of 30 digits) contains 22 as substring.

Together with 412623167243471, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (412623167243471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206311583621736 + 206311583621737.

It is an arithmetic number, because the mean of its divisors is an integer number (206311583621737).

Almost surely, 2412623167243473 is an apocalyptic number.

It is an amenable number.

412623167243473 is a deficient number, since it is larger than the sum of its proper divisors (1).

412623167243473 is an equidigital number, since it uses as much as digits as its factorization.

412623167243473 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 24385536, while the sum is 55.

The spelling of 412623167243473 in words is "four hundred twelve trillion, six hundred twenty-three billion, one hundred sixty-seven million, two hundred forty-three thousand, four hundred seventy-three".