Base | Representation |
---|---|
bin | 1100000000111000011… |
… | …01010011111100010001 |
3 | 1110110111001102101021022 |
4 | 12000130031103330101 |
5 | 23230343232041032 |
6 | 513344432405225 |
7 | 41552216026223 |
oct | 6003415237421 |
9 | 1413431371238 |
10 | 412790112017 |
11 | 14a077290908 |
12 | 680026a6815 |
13 | 2cc063a316a |
14 | 15d9cad4413 |
15 | ab0e6db512 |
hex | 601c353f11 |
412790112017 has 2 divisors, whose sum is σ = 412790112018. Its totient is φ = 412790112016.
The previous prime is 412790111983. The next prime is 412790112019. The reversal of 412790112017 is 710211097214.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 412717589761 + 72522256 = 642431^2 + 8516^2 .
It is a cyclic number.
It is not a de Polignac number, because 412790112017 - 28 = 412790111761 is a prime.
Together with 412790112019, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (412790112019) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206395056008 + 206395056009.
It is an arithmetic number, because the mean of its divisors is an integer number (206395056009).
Almost surely, 2412790112017 is an apocalyptic number.
It is an amenable number.
412790112017 is a deficient number, since it is larger than the sum of its proper divisors (1).
412790112017 is an equidigital number, since it uses as much as digits as its factorization.
412790112017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7056, while the sum is 35.
The spelling of 412790112017 in words is "four hundred twelve billion, seven hundred ninety million, one hundred twelve thousand, seventeen".
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