Base | Representation |
---|---|
bin | 1100000001010001111… |
… | …01010001111000111001 |
3 | 1110111000221220200102010 |
4 | 12000220331101320321 |
5 | 23231313011404423 |
6 | 513421553200133 |
7 | 41560424121456 |
oct | 6005075217071 |
9 | 1414027820363 |
10 | 413004013113 |
11 | 14a176aa897a |
12 | 68062260049 |
13 | 2cc3b7b6863 |
14 | 15dbd29482d |
15 | ab2338e693 |
hex | 6028f51e39 |
413004013113 has 16 divisors (see below), whose sum is σ = 563568572160. Its totient is φ = 268889782224.
The previous prime is 413004013073. The next prime is 413004013117. The reversal of 413004013113 is 311310400314.
It is not a de Polignac number, because 413004013113 - 29 = 413004012601 is a prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 413004013113.
It is not an unprimeable number, because it can be changed into a prime (413004013117) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 562498 + ... + 1068836.
It is an arithmetic number, because the mean of its divisors is an integer number (35223035760).
Almost surely, 2413004013113 is an apocalyptic number.
413004013113 is a gapful number since it is divisible by the number (43) formed by its first and last digit.
It is an amenable number.
413004013113 is a deficient number, since it is larger than the sum of its proper divisors (150564559047).
413004013113 is a wasteful number, since it uses less digits than its factorization.
413004013113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 512708.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 413004013113 its reverse (311310400314), we get a palindrome (724314413427).
The spelling of 413004013113 in words is "four hundred thirteen billion, four million, thirteen thousand, one hundred thirteen".
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