413004013117 has 2 divisors, whose sum is σ = 413004013118. Its totient is φ = 413004013116.

The previous prime is 413004013073. The next prime is 413004013139. The reversal of 413004013117 is 711310400314.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 370417087161 + 42586925956 = 608619^2 + 206366^2 .

It is a cyclic number.

It is not a de Polignac number, because 413004013117 - 2¹⁵ = 413003980349 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 413004013091 and 413004013100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (413004010117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206502006558 + 206502006559.

It is an arithmetic number, because the mean of its divisors is an integer number (206502006559).

Almost surely, 2^413004013117 is an apocalyptic number.

It is an amenable number.

413004013117 is a deficient number, since it is larger than the sum of its proper divisors (1).

413004013117 is an equidigital number, since it uses as much as digits as its factorization.

413004013117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

The spelling of 413004013117 in words is "four hundred thirteen billion, four million, thirteen thousand, one hundred seventeen".