4130040978373 has 2 divisors, whose sum is σ = 4130040978374. Its totient is φ = 4130040978372.

The previous prime is 4130040978367. The next prime is 4130040978377. The reversal of 4130040978373 is 3738790400314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2845098574564 + 1284942403809 = 1686742^2 + 1133553^2 .

It is a cyclic number.

It is not a de Polignac number, because 4130040978373 - 2⁵ = 4130040978341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4130040978377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065020489186 + 2065020489187.

It is an arithmetic number, because the mean of its divisors is an integer number (2065020489187).

Almost surely, 2^{4130040978373} is an apocalyptic number.

It is an amenable number.

4130040978373 is a deficient number, since it is larger than the sum of its proper divisors (1).

4130040978373 is an equidigital number, since it uses as much as digits as its factorization.

4130040978373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1524096, while the sum is 49.

The spelling of 4130040978373 in words is "four trillion, one hundred thirty billion, forty million, nine hundred seventy-eight thousand, three hundred seventy-three".