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4130113031417 is a prime number
BaseRepresentation
bin111100000110011101111…
…010111000110011111001
3112121211112200022112111202
4330012131322320303321
51020131432414001132
612441203035503545
7604251023346122
oct74063572706371
915554480275452
104130113031417
11135263115299a
1256853a5b7bb5
1323c611227359
14103c8182d049
1572678be9762
hex3c19deb8cf9

4130113031417 has 2 divisors, whose sum is σ = 4130113031418. Its totient is φ = 4130113031416.

The previous prime is 4130113031411. The next prime is 4130113031449. The reversal of 4130113031417 is 7141303110314.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2767794541561 + 1362318489856 = 1663669^2 + 1167184^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4130113031417 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4130113031417.

It is not a weakly prime, because it can be changed into another prime (4130113031411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065056515708 + 2065056515709.

It is an arithmetic number, because the mean of its divisors is an integer number (2065056515709).

Almost surely, 24130113031417 is an apocalyptic number.

It is an amenable number.

4130113031417 is a deficient number, since it is larger than the sum of its proper divisors (1).

4130113031417 is an equidigital number, since it uses as much as digits as its factorization.

4130113031417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3024, while the sum is 29.

The spelling of 4130113031417 in words is "four trillion, one hundred thirty billion, one hundred thirteen million, thirty-one thousand, four hundred seventeen".