Base | Representation |
---|---|
bin | 111100000110011101111… |
… | …010111000110100011001 |
3 | 112121211112200022112112221 |
4 | 330012131322320310121 |
5 | 1020131432414001244 |
6 | 12441203035504041 |
7 | 604251023346166 |
oct | 74063572706431 |
9 | 15554480275487 |
10 | 4130113031449 |
11 | 1352631152a19 |
12 | 56853a5b8021 |
13 | 23c611227382 |
14 | 103c8182d06d |
15 | 72678be9784 |
hex | 3c19deb8d19 |
4130113031449 has 2 divisors, whose sum is σ = 4130113031450. Its totient is φ = 4130113031448.
The previous prime is 4130113031417. The next prime is 4130113031453. The reversal of 4130113031449 is 9441303110314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4086057960000 + 44055071449 = 2021400^2 + 209893^2 .
It is a cyclic number.
It is not a de Polignac number, because 4130113031449 - 25 = 4130113031417 is a prime.
It is not a weakly prime, because it can be changed into another prime (4130113032449) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065056515724 + 2065056515725.
It is an arithmetic number, because the mean of its divisors is an integer number (2065056515725).
Almost surely, 24130113031449 is an apocalyptic number.
It is an amenable number.
4130113031449 is a deficient number, since it is larger than the sum of its proper divisors (1).
4130113031449 is an equidigital number, since it uses as much as digits as its factorization.
4130113031449 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 4130113031449 in words is "four trillion, one hundred thirty billion, one hundred thirteen million, thirty-one thousand, four hundred forty-nine".
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