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41301133335149 is a prime number
BaseRepresentation
bin10010110010000001010110…
…11000011001101001101101
312102020100102222211212002112
421121000223120121221231
520403134210113211044
6223501251223133405
711461623404650262
oct1131005330315155
9172210388755075
1041301133335149
111218379205a786
124770529ba4265
131a078ac4148cc
14a2adb239d269
154b950d3b009e
hex25902b619a6d

41301133335149 has 2 divisors, whose sum is σ = 41301133335150. Its totient is φ = 41301133335148.

The previous prime is 41301133335113. The next prime is 41301133335169. The reversal of 41301133335149 is 94153333110314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40497403155049 + 803730180100 = 6363757^2 + 896510^2 .

It is a cyclic number.

It is not a de Polignac number, because 41301133335149 - 232 = 41296838367853 is a prime.

It is a super-2 number, since 2×413011333351492 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41301133335169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20650566667574 + 20650566667575.

It is an arithmetic number, because the mean of its divisors is an integer number (20650566667575).

Almost surely, 241301133335149 is an apocalyptic number.

It is an amenable number.

41301133335149 is a deficient number, since it is larger than the sum of its proper divisors (1).

41301133335149 is an equidigital number, since it uses as much as digits as its factorization.

41301133335149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 174960, while the sum is 41.

The spelling of 41301133335149 in words is "forty-one trillion, three hundred one billion, one hundred thirty-three million, three hundred thirty-five thousand, one hundred forty-nine".