41301133335151 has 4 divisors (see below), whose sum is σ = 41680042815400. Its totient is φ = 40922223854904.

The previous prime is 41301133335149. The next prime is 41301133335169. The reversal of 41301133335151 is 15153333110314.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 41301133335151 - 2¹ = 41301133335149 is a prime.

It is a super-3 number, since 3×41301133335151³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41301133335751) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189454739961 + ... + 189454740178.

It is an arithmetic number, because the mean of its divisors is an integer number (10420010703850).

Almost surely, 2^{41301133335151} is an apocalyptic number.

41301133335151 is a deficient number, since it is larger than the sum of its proper divisors (378909480249).

41301133335151 is a wasteful number, since it uses less digits than its factorization.

41301133335151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 378909480248.

The product of its (nonzero) digits is 24300, while the sum is 34.

Adding to 41301133335151 its reverse (15153333110314), we get a palindrome (56454466445465).

The spelling of 41301133335151 in words is "forty-one trillion, three hundred one billion, one hundred thirty-three million, three hundred thirty-five thousand, one hundred fifty-one".