Base | Representation |
---|---|
bin | 101110111101001001111001… |
… | …1001001001101101100001001 |
3 | 2000011101211112022010220211222 |
4 | 1131322103303021031230021 |
5 | 413114001320432101101 |
6 | 4022233113205331425 |
7 | 152666044214654342 |
oct | 13572236311155411 |
9 | 2004354468126758 |
10 | 413025314331401 |
11 | 10a66a063435232 |
12 | 3a3a70a6106b75 |
13 | 149601738b7695 |
14 | 73dc76367b0c9 |
15 | 32b3b09d7801b |
hex | 177a4f324db09 |
413025314331401 has 2 divisors, whose sum is σ = 413025314331402. Its totient is φ = 413025314331400.
The previous prime is 413025314331361. The next prime is 413025314331419. The reversal of 413025314331401 is 104133413520314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 404282441114176 + 8742873217225 = 20106776^2 + 2956835^2 .
It is a cyclic number.
It is not a de Polignac number, because 413025314331401 - 242 = 408627267820297 is a prime.
It is not a weakly prime, because it can be changed into another prime (413025314331431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206512657165700 + 206512657165701.
It is an arithmetic number, because the mean of its divisors is an integer number (206512657165701).
Almost surely, 2413025314331401 is an apocalyptic number.
It is an amenable number.
413025314331401 is a deficient number, since it is larger than the sum of its proper divisors (1).
413025314331401 is an equidigital number, since it uses as much as digits as its factorization.
413025314331401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 413025314331401 its reverse (104133413520314), we get a palindrome (517158727851715).
The spelling of 413025314331401 in words is "four hundred thirteen trillion, twenty-five billion, three hundred fourteen million, three hundred thirty-one thousand, four hundred one".
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