Base | Representation |
---|---|
bin | 101110111101001001111001… |
… | …1001001001101101100001000 |
3 | 2000011101211112022010220211221 |
4 | 1131322103303021031230020 |
5 | 413114001320432101100 |
6 | 4022233113205331424 |
7 | 152666044214654341 |
oct | 13572236311155410 |
9 | 2004354468126757 |
10 | 413025314331400 |
11 | 10a66a063435231 |
12 | 3a3a70a6106b74 |
13 | 149601738b7694 |
14 | 73dc76367b0c8 |
15 | 32b3b09d7801a |
hex | 177a4f324db08 |
413025314331400 has 48 divisors (see below), whose sum is σ = 961504038977040. Its totient is φ = 165000201748800.
The previous prime is 413025314331361. The next prime is 413025314331401. The reversal of 413025314331400 is 4133413520314.
It is not an unprimeable number, because it can be changed into a prime (413025314331401) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1311867106 + ... + 1312181905.
It is an arithmetic number, because the mean of its divisors is an integer number (20031334145355).
Almost surely, 2413025314331400 is an apocalyptic number.
413025314331400 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
413025314331400 is an abundant number, since it is smaller than the sum of its proper divisors (548478724645640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
413025314331400 is a wasteful number, since it uses less digits than its factorization.
413025314331400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2624049814 (or 2624049805 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 413025314331400 its reverse (4133413520314), we get a palindrome (417158727851714).
The spelling of 413025314331400 in words is "four hundred thirteen trillion, twenty-five billion, three hundred fourteen million, three hundred thirty-one thousand, four hundred".
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