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413030033554441 is a prime number
BaseRepresentation
bin101110111101001100000110…
…0011011100111110000001001
32000011102021201012012021211111
41131322120030123213300021
5413114041002042220231
64022235213350530321
7152666302160464162
oct13572301433476011
92004367635167744
10413030033554441
1110a6710652a8366
123a3a7ba26669a1
1314960746519054
1473dca90330769
1532b3cd431b4b1
hex177a60c6e7c09

413030033554441 has 2 divisors, whose sum is σ = 413030033554442. Its totient is φ = 413030033554440.

The previous prime is 413030033554277. The next prime is 413030033554451. The reversal of 413030033554441 is 144455330030314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 403722018337225 + 9308015217216 = 20092835^2 + 3050904^2 .

It is a cyclic number.

It is not a de Polignac number, because 413030033554441 - 227 = 413029899336713 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 413030033554394 and 413030033554403.

It is not a weakly prime, because it can be changed into another prime (413030033554451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206515016777220 + 206515016777221.

It is an arithmetic number, because the mean of its divisors is an integer number (206515016777221).

Almost surely, 2413030033554441 is an apocalyptic number.

It is an amenable number.

413030033554441 is a deficient number, since it is larger than the sum of its proper divisors (1).

413030033554441 is an equidigital number, since it uses as much as digits as its factorization.

413030033554441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 518400, while the sum is 40.

Adding to 413030033554441 its reverse (144455330030314), we get a palindrome (557485363584755).

The spelling of 413030033554441 in words is "four hundred thirteen trillion, thirty billion, thirty-three million, five hundred fifty-four thousand, four hundred forty-one".